Uma função de foldtext bonita

Conforme mostrado acima, imprime o número de linhas dobradas à direita. Suportes signs, foldcolumn, nonumber, numbere relativenumber.

Aqui está um trecho do meu .vimrc. Pressione <Space>para dobrar. As dobras são baseadas na sintaxe.

if has("folding")
  set foldenable        " enable folding
  set foldmethod=syntax " fold based on syntax highlighting
  set foldlevelstart=99 " start editing with all folds open

  " toggle folds
  nnoremap <Space> za
  vnoremap <Space> za

  set foldtext=FoldText()
  function! FoldText()
    let l:lpadding = &fdc
    redir => l:signs
      execute 'silent sign place buffer='.bufnr('%')
    redir End
    let l:lpadding += l:signs =~ 'id=' ? 2 : 0

    if exists("+relativenumber")
      if (&number)
        let l:lpadding += max([&numberwidth, strlen(line('$'))]) + 1
      elseif (&relativenumber)
        let l:lpadding += max([&numberwidth, strlen(v:foldstart - line('w0')), strlen(line('w$') - v:foldstart), strlen(v:foldstart)]) + 1
      endif
    else
      if (&number)
        let l:lpadding += max([&numberwidth, strlen(line('$'))]) + 1
      endif
    endif

    " expand tabs
    let l:start = substitute(getline(v:foldstart), '\t', repeat(' ', &tabstop), 'g')
    let l:end = substitute(substitute(getline(v:foldend), '\t', repeat(' ', &tabstop), 'g'), '^\s*', '', 'g')

    let l:info = ' (' . (v:foldend - v:foldstart) . ')'
    let l:infolen = strlen(substitute(l:info, '.', 'x', 'g'))
    let l:width = winwidth(0) - l:lpadding - l:infolen

    let l:separator = ' … '
    let l:separatorlen = strlen(substitute(l:separator, '.', 'x', 'g'))
    let l:start = strpart(l:start , 0, l:width - strlen(substitute(l:end, '.', 'x', 'g')) - l:separatorlen)
    let l:text = l:start . ' … ' . l:end

    return l:text . repeat(' ', l:width - strlen(substitute(l:text, ".", "x", "g"))) . l:info
  endfunction
endif